Biamping Without a Crossover

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Member Since: Mar 17, 2008

Rob and all again.
Hi, the title might sound a little stupid, but I'm just trying to understand it fully.

EXAMPLE:

2 Speakers 500W @8Ohms
(400W LF / 100W HF)
NL4 Connectors x2 with "BIAMP" switch
2 Amps 600W @8ohms

1) Can we and how to hook up in Biamp mode using a bunch of 4-wire NL4s?

2) Can this be achieved without a crossover?

3) If can, means Channel A/B of Amp A is discharging 600W to my speakers 500W LF load? And Channels A/B of Amp B is discharging 600W into my speakers 100W HF load?

If so, wouldn't the HF drivers/horns be receiving too much power and potentially damaging the driver? If so, means, I have to use a smaller wattage amp for my HF in this example??

Thanks. All comments, critics and suggestions are welcomed!

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The Czar of BS
Member
Since: Dec 31, 2007


Sep 02, 2008 12:27 pm

No. It is not just a matter of wattage. It is also the frequencies that are being sent to each of the drivers. The crossover separates the frequency bands, then sends them to the appropriate driver.

If 50hz 60 will kill ya.
Member
Since: Jan 08, 2009


Jan 08, 2009 06:51 pm

PR HOT COLD
1 red blk
2 grn wht
3 orn blu
4 yel brn

(using a bunch of 4-wire NL4s) this is for 4s and 8s 4s just use 1 and 2. In bi-amp mode your 1 + and - will goto lows and your 2 + and - will goto highs. If you went to home depot, bought a spool of 14-4 and made your own, then start by following the color code. signal goes into the crossover, comes out low left and right to an amp left and right to pin 1 + and -. comes out high left and right to another amp left and right to pin 2+ and - Polarity matters here!

answer to #1 yes, 4 wire speakons but only 2, not a bunch. 1 to each speaker.
answer to #2 nope.
answer to #3, your amps are fine, better more power than less. pull the high outs back a bit on the x-over, no prob.

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